X^2+8x+3x+6=180

Solution for X^2+8x+3x+6=180 equation:

X^2+8X+3X+6=180

We move all terms to the left:

X^2+8X+3X+6-(180)=0

We add all the numbers together, and all the variables

X^2+11X-174=0

a = 1; b = 11; c = -174;
Δ = b2-4ac
Δ = 112-4·1·(-174)
Δ = 817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{817}}{2*1}=\frac{-11-\sqrt{817}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{817}}{2*1}=\frac{-11+\sqrt{817}}{2}
$